t=-16t^2+50t+700

Solution for t=-16t^2+50t+700 equation:

t=-16t^2+50t+700

We move all terms to the left:

t-(-16t^2+50t+700)=0

We get rid of parentheses

16t^2-50t+t-700=0

We add all the numbers together, and all the variables

16t^2-49t-700=0

a = 16; b = -49; c = -700;
Δ = b2-4ac
Δ = -492-4·16·(-700)
Δ = 47201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{47201}}{2*16}=\frac{49-\sqrt{47201}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{47201}}{2*16}=\frac{49+\sqrt{47201}}{32}
$